The product formed in the reaction is:

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(A) $NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce esters. In the given molecule,there is a

Vedclass · Accepted Answer

$4-$hydroxycyclohexanecarboxylic acid methyl ester

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(A) $NaBH_4$ is a selective reducing agent that reduces aldehydes and ketones to alcohols but does not reduce esters. In the given molecule,there is a ketone group and an ester group. $NaBH_4$ will selectively reduce the ketone group to a secondary alcohol while leaving the ester group intact. Therefore,the product is $4-$hydroxycyclohexanecarboxylic acid methyl ester.

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